x^3-8x^2+41x=0

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Solution for x^3-8x^2+41x=0 equation:


Simplifying
x3 + -8x2 + 41x = 0

Reorder the terms:
41x + -8x2 + x3 = 0

Solving
41x + -8x2 + x3 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(41 + -8x + x2) = 0

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(41 + -8x + x2)' equal to zero and attempt to solve: Simplifying 41 + -8x + x2 = 0 Solving 41 + -8x + x2 = 0 Begin completing the square. Move the constant term to the right: Add '-41' to each side of the equation. 41 + -8x + -41 + x2 = 0 + -41 Reorder the terms: 41 + -41 + -8x + x2 = 0 + -41 Combine like terms: 41 + -41 = 0 0 + -8x + x2 = 0 + -41 -8x + x2 = 0 + -41 Combine like terms: 0 + -41 = -41 -8x + x2 = -41 The x term is -8x. Take half its coefficient (-4). Square it (16) and add it to both sides. Add '16' to each side of the equation. -8x + 16 + x2 = -41 + 16 Reorder the terms: 16 + -8x + x2 = -41 + 16 Combine like terms: -41 + 16 = -25 16 + -8x + x2 = -25 Factor a perfect square on the left side: (x + -4)(x + -4) = -25 Can't calculate square root of the right side. The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

x = {0}

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